What is -x^2+6x-5>= 0 ?

The solution to -x^2+6x-5>= 0 is 1<= x<= 5

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-x^2+6x-5>= 0

- x^{2} + 6 x - 5 \geq 0

1 \leq x \leq 5

Interval Notation

[1, 5]

Solution steps

- x^{2} + 6 x - 5 \geq 0

Factor

- x^{2} + 6 x - 5 : - (x - 1) (x - 5)

- (x - 1) (x - 5) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x - 5)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x - 5) \leq 0

Identify the intervals

1 \leq x \leq 5

(\frac{y}{4})^{2}

1 \leq 2 ∣ x + 3 ∣ \leq 5

\frac{2}{7} + \frac{5}{14}

3 x^{3} - 13 x^{2} + 43 x - 13

\frac{y}{6} \leq 2