What are the solutions to the equation 3x^2+8x-4=0 ?

The solutions to the equation 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3

Find the zeros of 3x^2+8x-4=0

The zeros of 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3

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3 x^{2} + 8 x - 4 = 0

x = \frac{2 ( 7 - 2 )}{3}, x = - \frac{2 ( 2 + 7 )}{3}

Decimal Notation

x = 0.43050 \dots, x = - 3.09716 \dots

Solution steps

3 x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 4) = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 \cdot 3}, x_{2} = \frac{- 8 - 4 7}{2 \cdot 3}

x = \frac{- 8 + 4 7}{2 \cdot 3} : \frac{2 ( 7 - 2 )}{3}

x = \frac{- 8 - 4 7}{2 \cdot 3} : - \frac{2 ( 2 + 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 7 - 2 )}{3}, x = - \frac{2 ( 2 + 7 )}{3}

x^{2} - 4 x = 0

5 y^{2} - 2 y - 3 = 0

4 (x - 1)^{2} + \frac{1}{3} = \frac{7}{9}

x^{2} + 10 x - 600 = 0

8 + 8 p \geq - 152

What are the solutions to the equation 3x^2+8x-4=0 ?
The solutions to the equation 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3
Find the zeros of 3x^2+8x-4=0
The zeros of 3x^2+8x-4=0 are x=(2(sqrt(7)-2))/3 ,x=-(2(2+sqrt(7)))/3