What is ((x+2)^2)/4+((y-1)^2)/(25)=1 ?

The solution to ((x+2)^2)/4+((y-1)^2)/(25)=1 is Ellipse with (h,k)=(-2,1),a=2,b=5

Popular >

((x+2)^2)/4+((y-1)^2)/(25)=1

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{25} = 1

(h, k) = (- 2, 1), a = 2, b = 5

Solution steps

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} + \frac{( y - 1 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 1), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 1), b = 5, a = 2

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 2

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

2 x^{2} + 4 y^{2} + 14 x + 8 y + 16 = 0

\frac{( x + 1 ) ^{2} + ( y - 1 ) ^{2}}{( x - 2 ) ^{2} + ( y + 1 ) ^{2}} = 9

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{4} = 1

What is ((x+2)^2)/4+((y-1)^2)/(25)=1 ?
The solution to ((x+2)^2)/4+((y-1)^2)/(25)=1 is Ellipse with (h,k)=(-2,1),a=2,b=5