What is ((x^2))/((16))+((y^2))/((25))=1 ?

The solution to ((x^2))/((16))+((y^2))/((25))=1 is Ellipse with (h,k)=(0,0),a=4,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x^2))/((16))+((y^2))/((25))=1

\frac{( x ^{2} )}{( 16 )} + \frac{( y ^{2} )}{( 25 )} = 1

(h, k) = (0, 0), a = 4, b = 5

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 4

- y = x^{2} + y^{2}

\frac{( x - 7 ) ^{2}}{81} + \frac{( y ) ^{2}}{9} = 1

4 - x^{2} - 4 y^{2} = 1

x (100 - 3 x) + y (192 - 6 y) = 0

X^{2} + \frac{Y ^{2}}{49} = 1

What is ((x^2))/((16))+((y^2))/((25))=1 ?
The solution to ((x^2))/((16))+((y^2))/((25))=1 is Ellipse with (h,k)=(0,0),a=4,b=5