What is 4/9 \div (1-3/7) ?

The solution to 4/9 \div (1-3/7) is 7/9

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4/9 \div (1-3/7)

\frac{4}{9} \div (1 - \frac{3}{7})

\frac{7}{9}

Solution steps

\frac{4}{9} \div (1 - \frac{3}{7})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{3}{7}) : \frac{4}{7}

1 - \frac{3}{7}

1 - \frac{3}{7} = \frac{4}{7}

1 - \frac{3}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} - \frac{3}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 - 3}{7}

1 \cdot 7 - 3 = 4

1 \cdot 7 - 3

Multiply the numbers:

1 \cdot 7 = 7

= 7 - 3

Subtract the numbers:

7 - 3 = 4

= 4

= \frac{4}{7}

= \frac{4}{7}

= \frac{4}{9} \div \frac{4}{7}

Multiply and divide (left to right)

\frac{4}{9} \div \frac{4}{7} : \frac{7}{9}

\frac{4}{9} \div \frac{4}{7}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{4}{9} \cdot \frac{7}{4}

Cross-cancel:

4

= \frac{7}{9}

= \frac{7}{9}

(9 - 7)^{2}

(43 + 853) \div 81

2 (- 1)^{2} + 8 (- 1) + 10

\frac{1}{2} (1 - 2)^{2} - 4

(- 3)^{2} + 2 (- 3) + 2