What is -6(1-3)+{-4+7-5(2+7)-[5-9-4(1-4)]}-12 ?

The solution to -6(1-3)+{-4+7-5(2+7)-[5-9-4(1-4)]}-12 is -50

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-6(1-3)+{-4+7-5(2+7)-[5-9-4(1-4)]}-12

- 6 (1 - 3) + {- 4 + 7 - 5 (2 + 7) - [5 - 9 - 4 (1 - 4)]} - 12

- 50

Solution steps

- 6 (1 - 3) + {- 4 + 7 - 5 (2 + 7) - [5 - 9 - 4 (1 - 4)]} - 12

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - 3) : - 2

1 - 3

1 - 3 = - 2

= - 2

= - 6 (- 2) + {- 4 + 7 - 5 (2 + 7) - [5 - 9 - 4 (1 - 4)]} - 12

Calculate within parentheses

{- 4 + 7 - 5 (2 + 7) - [5 - 9 - 4 (1 - 4)]} : - 50

- 4 + 7 - 5 (2 + 7) - [5 - 9 - 4 (1 - 4)]

Calculate within parentheses

(2 + 7) : 9

2 + 7

2 + 7 = 9

= 9

= - 4 + 7 - 5 \cdot 9 - [5 - 9 - 4 (1 - 4)]

Calculate within parentheses

[5 - 9 - 4 (1 - 4)] : 8

5 - 9 - 4 (1 - 4)

Calculate within parentheses

(1 - 4) : - 3

1 - 4

1 - 4 = - 3

= - 3

= 5 - 9 - 4 (- 3)

Multiply and divide (left to right)

4 (- 3) : - 12

4 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 3) = - 4 \cdot 3 = - 12

= - 12

= 5 - 9 - (- 12)

Add and subtract (left to right)

5 - 9 - (- 12) : 8

5 - 9 - (- 12)

5 - 9 = - 4

= - 4 - (- 12)

Apply rule

- (- a) = + a

- (- 12) = + 12

= - 4 + 12

- 4 + 12 = 8

= 8

= 8

= - 4 + 7 - 5 \cdot 9 - 8

Multiply and divide (left to right)

5 \cdot 9 : 45

5 \cdot 9

5 \cdot 9 = 45

= 45

= - 4 + 7 - 45 - 8

Add and subtract (left to right)

- 4 + 7 - 45 - 8 : - 50

- 4 + 7 - 45 - 8

- 4 + 7 = 3

= 3 - 45 - 8

3 - 45 = - 42

= - 42 - 8

- 42 - 8 = - 50

= - 50

= - 50

= - 6 (- 2) - 50 - 12

Multiply and divide (left to right)

- 6 (- 2) : 12

- 6 (- 2)

Apply rule

- a \cdot (- b) = a \cdot b

- 6 (- 2) = 6 \cdot 2 = 12

= 12

= 12 - 50 - 12

Add and subtract (left to right)

12 - 50 - 12 : - 50

12 - 50 - 12

12 - 50 = - 38

= - 38 - 12

- 38 - 12 = - 50

= - 50

= - 50

\frac{24}{2}

(4 - 2)^{2}

10 - 8 + (6 \cdot 7) - 9

2 - 10 + 8 - (- 2)

\frac{12}{14}

What is -6(1-3)+{-4+7-5(2+7)-[5-9-4(1-4)]}-12 ?
The solution to -6(1-3)+{-4+7-5(2+7)-[5-9-4(1-4)]}-12 is -50