What is 5-4 3/4+1/4 ?

The solution to 5-4 3/4+1/4 is 1/2

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5-4 3/4+1/4

5 - 4 \frac{3}{4} + \frac{1}{4}

\frac{1}{2}

Solution steps

5 - 4 \frac{3}{4} + \frac{1}{4}

Convert mixed numbers to improper fractions:

4 \frac{3}{4} = \frac{19}{4}

4 \frac{3}{4}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

4 \frac{3}{4} = \frac{4 \cdot 4 + 3}{4}

= \frac{19}{4}

= 5 - \frac{19}{4} + \frac{1}{4}

Follow the PEMDAS order of operations

Add and subtract (left to right)

5 - \frac{19}{4} + \frac{1}{4} : \frac{1}{2}

5 - \frac{19}{4} + \frac{1}{4}

5 - \frac{19}{4} = \frac{1}{4}

5 - \frac{19}{4}

Convert element to fraction:

5 = \frac{5 \cdot 4}{4}

= \frac{5 \cdot 4}{4} - \frac{19}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 4 - 19}{4}

5 \cdot 4 - 19 = 1

5 \cdot 4 - 19

Multiply the numbers:

5 \cdot 4 = 20

= 20 - 19

Subtract the numbers:

20 - 19 = 1

= 1

= \frac{1}{4}

= \frac{1}{4} + \frac{1}{4}

\frac{1}{4} + \frac{1}{4} = \frac{1}{2}

\frac{1}{4} + \frac{1}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 1}{4}

Add the numbers:

1 + 1 = 2

= \frac{2}{4}

Cancel the common factor:

2

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

36 \div 3 (8 - 6) \div 6

[(- 3) + (- 2) \times 3] \div [5 + 2 \times (- 1)]

2 (1) - 2

2^{3} + 3^{3}

2^{2} \times 5^{2}