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Popular >

4cos^2(60)+sqrt(3)tan(30)

Solución

4 cos^{2} (6 0^{\circ}) + 3 tan (3 0^{\circ})

Solución

2

Pasos de solución

4 cos^{2} (6 0^{\circ}) + 3 tan (3 0^{\circ})

Utilizar la siguiente identidad trivial:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

Utilizar la siguiente identidad trivial:

tan (3 0^{\circ}) = \frac{3}{3}

tan (3 0^{\circ})

tan (x)

tabla de valores periódicos con

18 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= \frac{3}{3}

= 4 (\frac{1}{2})^{2} + 3 \frac{3}{3}

Simplificar

4 (\frac{1}{2})^{2} + 3 \frac{3}{3} : 2

4 (\frac{1}{2})^{2} + 3 \frac{3}{3}

4 (\frac{1}{2})^{2} = 1

4 (\frac{1}{2})^{2}

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Aplicar la regla

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= 4 \cdot \frac{1}{2 ^{2}}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2 ^{2}}

Multiplicar los numeros:

1 \cdot 4 = 4

= \frac{4}{2 ^{2}}

Factorizar

4 : 2^{2}

Factorizar

4 = 2^{2}

= \frac{2 ^{2}}{2 ^{2}}

Eliminar los terminos comunes:

2^{2}

= 1

3 \frac{3}{3} = 1

3 \frac{3}{3}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 3}{3}

33 = 3

33

Aplicar las leyes de los exponentes:

a a = a

33 = 3

= 3

= \frac{3}{3}

Aplicar la regla

\frac{a}{a} = 1

= 1

= 1 + 1

Sumar:

1 + 1 = 2

= 2

= 2

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