es

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,cos(a+b)=(sqrt(3))/2

Solución

resolver para

a, cos (a + b) = \frac{3}{2}

Solución

a = \frac{π}{6} + 2 πn - b, a = \frac{11 π}{6} + 2 πn - b

Pasos de solución

cos (a + b) = \frac{3}{2}

Soluciones generales para

cos (a + b) = \frac{3}{2}

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

a + b = \frac{π}{6} + 2 πn, a + b = \frac{11 π}{6} + 2 πn

a + b = \frac{π}{6} + 2 πn, a + b = \frac{11 π}{6} + 2 πn

Resolver

a + b = \frac{π}{6} + 2 πn : a = \frac{π}{6} + 2 πn - b

a + b = \frac{π}{6} + 2 πn

Mover

b

al lado derecho

a + b = \frac{π}{6} + 2 πn

Restar

b

de ambos lados

a + b - b = \frac{π}{6} + 2 πn - b

Simplificar

a = \frac{π}{6} + 2 πn - b

a = \frac{π}{6} + 2 πn - b

Resolver

a + b = \frac{11 π}{6} + 2 πn : a = \frac{11 π}{6} + 2 πn - b

a + b = \frac{11 π}{6} + 2 πn

Mover

b

al lado derecho

a + b = \frac{11 π}{6} + 2 πn

Restar

b

de ambos lados

a + b - b = \frac{11 π}{6} + 2 πn - b

Simplificar

a = \frac{11 π}{6} + 2 πn - b

a = \frac{11 π}{6} + 2 πn - b

a = \frac{π}{6} + 2 πn - b, a = \frac{11 π}{6} + 2 πn - b

Ejemplos populares

sin (30 x) = - 0.6

4cos(θ)+1=2cos(θ)

4 cos (θ) + 1 = 2 cos (θ)

csc(x)-sin(x)=cot(x)csc(x)

csc (x) - sin (x) = cot (x) csc (x)

4-4sin(θ)=4cos(θ)

4 - 4 sin (θ) = 4 cos (θ)

sec^2(x)-2tan(x)-4=0

sec^{2} (x) - 2 tan (x) - 4 = 0