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Popular >

(tan(x)+cos(x))/((1+sin(x)))= 1/(cos(x))

Solución

\frac{tan ( x ) + cos ( x )}{( 1 + sin ( x ) )} = \frac{1}{cos ( x )}

Solución

x = 2 πn, x = π + 2 πn

Grados

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Pasos de solución

\frac{tan ( x ) + cos ( x )}{( 1 + sin ( x ) )} = \frac{1}{cos ( x )}

Restar

\frac{1}{cos ( x )}

de ambos lados

\frac{tan ( x ) + cos ( x )}{1 + sin ( x )} - \frac{1}{cos ( x )} = 0

Simplificar

\frac{tan ( x ) + cos ( x )}{1 + sin ( x )} - \frac{1}{cos ( x )} : \frac{cos ( x ) tan ( x ) + cos ^{2} ( x ) - sin ( x ) - 1}{cos ( x ) ( sin ( x ) + 1 )}

\frac{tan ( x ) + cos ( x )}{1 + sin ( x )} - \frac{1}{cos ( x )}

Mínimo común múltiplo de

1 + sin (x), cos (x) : cos (x) (sin (x) + 1)

1 + sin (x), cos (x)

Mínimo común múltiplo (MCM)

Calcular una expresión que este compuesta de factores que aparezcan tanto en

1 + sin (x)

cos (x)

= cos (x) (sin (x) + 1)

Reescribir las fracciones basandose en el mínimo común denominador

Multiplicar cada numerador por la misma cantidad necesaria para multiplicar el denominador correspondiente y convertirlo en el mínimo común denominador

Para

\frac{tan ( x ) + cos ( x )}{1 + sin ( x )} :

multiplicar el denominador y el numerador por

cos (x)

\frac{tan ( x ) + cos ( x )}{1 + sin ( x )} = \frac{( tan ( x ) + cos ( x ) ) cos ( x )}{( 1 + sin ( x ) ) cos ( x )}

Para

\frac{1}{cos ( x )} :

multiplicar el denominador y el numerador por

sin (x) + 1

\frac{1}{cos ( x )} = \frac{1 \cdot ( sin ( x ) + 1 )}{cos ( x ) ( sin ( x ) + 1 )} = \frac{sin ( x ) + 1}{cos ( x ) ( sin ( x ) + 1 )}

= \frac{( tan ( x ) + cos ( x ) ) cos ( x )}{( 1 + sin ( x ) ) cos ( x )} - \frac{sin ( x ) + 1}{cos ( x ) ( sin ( x ) + 1 )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( tan ( x ) + cos ( x ) ) cos ( x ) - ( sin ( x ) + 1 )}{cos ( x ) ( sin ( x ) + 1 )}

Expandir

(tan (x) + cos (x)) cos (x) - (sin (x) + 1) : cos (x) tan (x) + cos^{2} (x) - sin (x) - 1

(tan (x) + cos (x)) cos (x) - (sin (x) + 1)

= cos (x) (tan (x) + cos (x)) - (sin (x) + 1)

Expandir

cos (x) (tan (x) + cos (x)) : cos (x) tan (x) + cos^{2} (x)

cos (x) (tan (x) + cos (x))

Poner los parentesis utilizando:

a (b + c) = ab + a c

a = cos (x), b = tan (x), c = cos (x)

= cos (x) tan (x) + cos (x) cos (x)

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

Sumar:

1 + 1 = 2

= cos^{2} (x)

= cos (x) tan (x) + cos^{2} (x)

= cos (x) tan (x) + cos^{2} (x) - (sin (x) + 1)

- (sin (x) + 1) : - sin (x) - 1

- (sin (x) + 1)

Poner los parentesis

= - (sin (x)) - (1)

Aplicar las reglas de los signos

+ (- a) = - a

= - sin (x) - 1

= cos (x) tan (x) + cos^{2} (x) - sin (x) - 1

= \frac{cos ( x ) tan ( x ) + cos ^{2} ( x ) - sin ( x ) - 1}{cos ( x ) ( sin ( x ) + 1 )}

\frac{cos ( x ) tan ( x ) + cos ^{2} ( x ) - sin ( x ) - 1}{cos ( x ) ( sin ( x ) + 1 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (x) tan (x) + cos^{2} (x) - sin (x) - 1 = 0

Re-escribir usando identidades trigonométricas

- 1 + cos^{2} (x) - sin (x) + cos (x) tan (x)

Utilizar la identidad trigonométrica básica:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - 1 + cos^{2} (x) - sin (x) + cos (x) \frac{sin ( x )}{cos ( x )}

Simplificar

- 1 + cos^{2} (x) - sin (x) + cos (x) \frac{sin ( x )}{cos ( x )} : - 1 + cos^{2} (x)

- 1 + cos^{2} (x) - sin (x) + cos (x) \frac{sin ( x )}{cos ( x )}

cos (x) \frac{sin ( x )}{cos ( x )} = sin (x)

cos (x) \frac{sin ( x )}{cos ( x )}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) cos ( x )}{cos ( x )}

Eliminar los terminos comunes:

cos (x)

= sin (x)

= - 1 + cos^{2} (x) - sin (x) + sin (x)

Sumar elementos similares:

- sin (x) + sin (x) = 0

= - 1 + cos^{2} (x)

= - 1 + cos^{2} (x)

- 1 + cos^{2} (x) = 0

Usando el método de sustitución

- 1 + cos^{2} (x) = 0

Sea:

cos (x) = u

- 1 + u^{2} = 0

- 1 + u^{2} = 0 : u = 1, u = - 1

- 1 + u^{2} = 0

Mover

1

al lado derecho

- 1 + u^{2} = 0

Sumar

1

a ambos lados

- 1 + u^{2} + 1 = 0 + 1

Simplificar

u^{2} = 1

u^{2} = 1

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = 1, u = - 1

1 = 1

1

Aplicar la regla

1 = 1

= 1

- 1 = - 1

- 1

Aplicar la regla

1 = 1

= - 1

u = 1, u = - 1

Sustituir en la ecuación

u = cos (x)

cos (x) = 1, cos (x) = - 1

cos (x) = 1, cos (x) = - 1

cos (x) = 1 : x = 2 πn

cos (x) = 1

Soluciones generales para

cos (x) = 1

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

cos (x) = - 1 : x = π + 2 πn

cos (x) = - 1

Soluciones generales para

cos (x) = - 1

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = π + 2 πn

x = π + 2 πn

Combinar toda las soluciones

x = 2 πn, x = π + 2 πn

Ejemplos populares

sin(θ)= 4/5 ,0<= θ<= pi/2

sin (θ) = \frac{4}{5}, 0 \leq θ \leq \frac{π}{2}

-cos^2(x)+cos(x)+2=0

- cos^{2} (x) + cos (x) + 2 = 0

2-cos^2(x)=4sin^2(1/2 x)

2 - cos^{2} (x) = 4 sin^{2} (\frac{1}{2} x)

((tan(x)+2sin(x)))/((tan(x)-2sin(x)))=3

\frac{( tan ( x ) + 2 sin ( x ) )}{( tan ( x ) - 2 sin ( x ) )} = 3

sin^{(2)}(x)+cos(x)+1=0

sin^{(2)} (x) + cos (x) + 1 = 0