es

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

csc(θ)=(sqrt(20))/4

Solución

csc (θ) = \frac{20}{4}

Solución

θ = 1.10714 \dots + 2 πn, θ = π - 1.10714 \dots + 2 πn

+1

radianes

θ = 1.10714 \dots + 6.28318 \dots n, θ = π - 1.10714 \dots + 6.28318 \dots n

Pasos de solución

csc (θ) = \frac{20}{4}

Simplificar

\frac{20}{4} : \frac{5}{2}

\frac{20}{4}

Factorizar

20 : 25

Factorizar

20 = 2^{2} \cdot 5

= 2^{2} \cdot 5

Aplicar las leyes de los exponentes:

= 5 2^{2}

Simplificar

2^{2} : 2

2^{2}

Aplicar la siguiente propiedad de los radicales:

asumiendo que

a \geq 0

= 2

= 25

Factorizar

4 : 2^{2}

Factorizar

4 = 2^{2}

= \frac{2 5}{2 ^{2}}

Eliminar los terminos comunes:

2

= \frac{5}{2}

Aplicar propiedades trigonométricas inversas

csc (θ) = \frac{5}{2}

Soluciones generales para

csc (θ) = \frac{5}{2}

csc (x) = a \Rightarrow x = arccsc (a) + 2 πn, x = π - arccsc (a) + 2 πn

θ = arccsc (\frac{5}{2}) + 2 πn, θ = π - arccsc (\frac{5}{2}) + 2 πn

θ = arccsc (\frac{5}{2}) + 2 πn, θ = π - arccsc (\frac{5}{2}) + 2 πn

Mostrar soluciones en forma decimal

θ = 1.10714 \dots + 2 πn, θ = π - 1.10714 \dots + 2 πn

Ejemplos populares

sin(x+10)=cos(x+20)

sin (x + 1 0^{\circ}) = cos (x + 2 0^{\circ})

c^2=b^2+a^2-2(b)(a)cos(θ)

c^{2} = b^{2} + a^{2} - 2 (b) (a) cos (θ)

5cos(θ)=2+cos(θ)

5 cos (θ) = 2 + cos (θ)

cos (x + π) = 1

solvefor x,sin(4x)=-2(sin(2x))resolver para

x, sin (4 x) = - 2 (sin (2 x))