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solvefor A,sin(B+C/2)=cos(A/2)

Solución

resolver para

A, sin (B + \frac{C}{2}) = cos (\frac{A}{2})

Solución

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn, A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

Pasos de solución

sin (B + \frac{C}{2}) = cos (\frac{A}{2})

Intercambiar lados

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

Aplicar propiedades trigonométricas inversas

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

Soluciones generales para

cos (\frac{A}{2}) = sin (B + \frac{C}{2})

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn, \frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn, \frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Resolver

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn : A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn

Multiplicar ambos lados por

2

\frac{A}{2} = arccos (sin (B + \frac{C}{2})) + 2 πn

Multiplicar ambos lados por

2

\frac{2 A}{2} = 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplificar

\frac{2 A}{2} = 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplificar

\frac{2 A}{2} : A

\frac{2 A}{2}

Dividir:

\frac{2}{2} = 1

= A

Simplificar

2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn : 2 arccos (sin (B + \frac{C}{2})) + 4 πn

2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Multiplicar los numeros:

2 \cdot 2 = 4

= 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn

Resolver

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn : A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Multiplicar ambos lados por

2

\frac{A}{2} = - arccos (sin (B + \frac{C}{2})) + 2 πn

Multiplicar ambos lados por

2

\frac{2 A}{2} = - 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplificar

\frac{2 A}{2} = - 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Simplificar

\frac{2 A}{2} : A

\frac{2 A}{2}

Dividir:

\frac{2}{2} = 1

= A

Simplificar

- 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn : - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

- 2 arccos (sin (B + \frac{C}{2})) + 2 \cdot 2 πn

Multiplicar los numeros:

2 \cdot 2 = 4

= - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

A = 2 arccos (sin (B + \frac{C}{2})) + 4 πn, A = - 2 arccos (sin (B + \frac{C}{2})) + 4 πn

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3sqrt(3)tan(u)=3

33 tan (u) = 3

3 sec (2 x + 3) = 4

solvefor t,f=3cos(pttheta)-2 resolver para

t, f = 3 cos (ptt h e t a) - 2

sin(θ-pi)=-1/(sqrt(2))

sin (θ - π) = - \frac{1}{2}

7-2sin(5(x+pi/8))=9

7 - 2 sin (5 (x + \frac{π}{8})) = 9