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Beliebt >

(6cos(x)-5sin(x))^2+11sin^2(x)=36

Lösung

(6 cos (x) - 5 sin (x))^{2} + 11 sin^{2} (x) = 36

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Grad

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n, x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

(6 cos (x) - 5 sin (x))^{2} + 11 sin^{2} (x) = 36

Subtrahiere

36

von beiden Seiten

36 cos^{2} (x) - 60 cos (x) sin (x) + 36 sin^{2} (x) - 36 = 0

Umschreiben mit Hilfe von Trigonometrie-Identitäten

- 36 + 36 cos^{2} (x) + 36 sin^{2} (x) - 60 cos (x) sin (x)

Verwende die Pythagoreische Identität:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= - 36 + 36 (1 - sin^{2} (x)) + 36 sin^{2} (x) - 60 cos (x) sin (x)

Vereinfache

- 36 + 36 (1 - sin^{2} (x)) + 36 sin^{2} (x) - 60 cos (x) sin (x) : - 60 cos (x) sin (x)

- 36 + 36 (1 - sin^{2} (x)) + 36 sin^{2} (x) - 60 cos (x) sin (x)

Multipliziere aus

36 (1 - sin^{2} (x)) : 36 - 36 sin^{2} (x)

36 (1 - sin^{2} (x))

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = 36, b = 1, c = sin^{2} (x)

= 36 \cdot 1 - 36 sin^{2} (x)

Multipliziere die Zahlen:

36 \cdot 1 = 36

= 36 - 36 sin^{2} (x)

= - 36 + 36 - 36 sin^{2} (x) + 36 sin^{2} (x) - 60 cos (x) sin (x)

Vereinfache

- 36 + 36 - 36 sin^{2} (x) + 36 sin^{2} (x) - 60 cos (x) sin (x) : - 60 cos (x) sin (x)

- 36 + 36 - 36 sin^{2} (x) + 36 sin^{2} (x) - 60 cos (x) sin (x)

Addiere gleiche Elemente:

- 36 sin^{2} (x) + 36 sin^{2} (x) = 0

= - 36 + 36 - 60 cos (x) sin (x)

- 36 + 36 = 0

= - 60 cos (x) sin (x)

= - 60 cos (x) sin (x)

= - 60 cos (x) sin (x)

- 60 cos (x) sin (x) = 0

Löse jeden Teil einzeln

cos (x) = 0 or sin (x) = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 0

Allgemeine Lösung für

cos (x) = 0

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

Allgemeine Lösung für

sin (x) = 0

sin (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Löse

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

Kombiniere alle Lösungen

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

e^{s i n (x)} - 2 = 0

(3 cos (x) - 6 sin (x))^{2} - 27 sin^{2} (x) = - 9

cos (2 x) = \frac{( 3 k - 2 )}{3}

sin^{2} (x) - sin (x) = 0, ([0, 2 π])

3 (cos (x) - sin (x)) = 0