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cos(w)=0.75sin(90-w)

解答

cos (w) = 0.75 sin (9 0^{\circ} - w)

解答

w = 9 0^{\circ} + 36 0^{\circ} n, w = 27 0^{\circ} + 36 0^{\circ} n

+1

弧度

w = \frac{π}{2} + 2 πn, w = \frac{3 π}{2} + 2 πn

求解步骤

cos (w) = 0.75 sin (9 0^{\circ} - w)

使用三角恒等式改写

cos (w) = 0.75 sin (9 0^{\circ} - w)

使用三角恒等式改写

sin (9 0^{\circ} - w)

使用角差恒等式:

sin (s - t) = sin (s) cos (t) - cos (s) sin (t)

= sin (9 0^{\circ}) cos (w) - cos (9 0^{\circ}) sin (w)

化简

sin (9 0^{\circ}) cos (w) - cos (9 0^{\circ}) sin (w) : cos (w)

sin (9 0^{\circ}) cos (w) - cos (9 0^{\circ}) sin (w)

sin (9 0^{\circ}) cos (w) = cos (w)

sin (9 0^{\circ}) cos (w)

化简

sin (9 0^{\circ}) : 1

sin (9 0^{\circ})

使用以下普通恒等式:

sin (9 0^{\circ}) = 1

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1 \cdot cos (w)

乘以:

1 \cdot cos (w) = cos (w)

= cos (w)

cos (9 0^{\circ}) sin (w) = 0

cos (9 0^{\circ}) sin (w)

化简

cos (9 0^{\circ}) : 0

cos (9 0^{\circ})

使用以下普通恒等式:

cos (9 0^{\circ}) = 0

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= 0 \cdot sin (w)

使用法则

0 \cdot a = 0

= 0

= cos (w) - 0

cos (w) - 0 = cos (w)

= cos (w)

= cos (w)

cos (w) = 0.75 cos (w)

cos (w) = 0.75 cos (w)

两边减去

0.75 cos (w)

0.25 cos (w) = 0

在两边乘以

100

0.25 cos (w) = 0

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere are

2

digits to the right of the decimal point, therefore multiply by

100

0.25 cos (w) \cdot 100 = 0 \cdot 100

整理后得

25 cos (w) = 0

25 cos (w) = 0

两边除以

25

25 cos (w) = 0

两边除以

25

\frac{25 cos ( w )}{25} = \frac{0}{25}

化简

cos (w) = 0

cos (w) = 0

cos (w) = 0

的通解

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

w = 9 0^{\circ} + 36 0^{\circ} n, w = 27 0^{\circ} + 36 0^{\circ} n

w = 9 0^{\circ} + 36 0^{\circ} n, w = 27 0^{\circ} + 36 0^{\circ} n

流行的例子

csc (4 x) = 2

3tan^2(x)=2sec^2(x)+1,0<= x<= 180

3 tan^{2} (x) = 2 sec^{2} (x) + 1, 0^{\circ} \leq x \leq 18 0^{\circ}

2arctan(xe^{0/2})= pi/2

2 arctan (x e^{\frac{0}{2}}) = \frac{π}{2}

2sin(x)cos(x)-sqrt(2)cos(x)=0

2 sin (x) cos (x) - 2 cos (x) = 0

solvefor x,2cos(x)-sqrt(2)=0 求解

x, 2 cos (x) - 2 = 0