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Popular >

solvefor u,y=ccosh*sin(u)

Solución

resolver para

u, y = ccos h \cdot sin (u)

Solución

u = arcsin (\frac{y}{c ^{2} h os}) + 2 πn, u = π + arcsin (- \frac{y}{c ^{2} h os}) + 2 πn

Pasos de solución

y = ccos h sin (u)

Intercambiar lados

ccos h sin (u) = y

Simplificar

ccos h : c^{2} h os

ccos h

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

cc = c^{1 + 1}

= c^{1 + 1} os h

Sumar:

1 + 1 = 2

= c^{2} os h

c^{2} h os sin (u) = y

Dividir ambos lados entre

c^{2} h os; c \neq = 0

c^{2} h os sin (u) = y

Dividir ambos lados entre

c^{2} h os; c \neq = 0

\frac{c ^{2} h os sin ( u )}{c ^{2} h os} = \frac{y}{c ^{2} h os}; c \neq = 0

Simplificar

sin (u) = \frac{y}{c ^{2} h os}; c \neq = 0

sin (u) = \frac{y}{c ^{2} h os}; c \neq = 0

Aplicar propiedades trigonométricas inversas

sin (u) = \frac{y}{c ^{2} h os}

Soluciones generales para

sin (u) = \frac{y}{c ^{2} h os}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

u = arcsin (\frac{y}{c ^{2} h os}) + 2 πn, u = π + arcsin (- \frac{y}{c ^{2} h os}) + 2 πn

u = arcsin (\frac{y}{c ^{2} h os}) + 2 πn, u = π + arcsin (- \frac{y}{c ^{2} h os}) + 2 πn

Ejemplos populares

2cos(θ)+2sqrt(3)=sqrt(3)

2 cos (θ) + 23 = 3

-2sqrt(2)=-4sin(2θ)

- 22 = - 4 sin (2 θ)

8cos(x)=4cos^2(x)+3

8 cos (x) = 4 cos^{2} (x) + 3

(sin^2(x))/2+c=cos(x)c+c

\frac{sin ^{2} ( x )}{2} + c = cos (x) c + c

-tan(x)-sec(x)=0

- tan (x) - sec (x) = 0