English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec^2(θ)tan(θ)=2tan(θ),0<= θ<= 360

Solución

sec^{2} (θ) tan (θ) = 2 tan (θ), 0^{\circ} \leq θ \leq 36 0^{\circ}

Solución

θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}, θ = 13 5^{\circ}, θ = 22 5^{\circ}, θ = 4 5^{\circ}, θ = 31 5^{\circ}

radianes

θ = 0, θ = π, θ = 2 π, θ = \frac{3 π}{4}, θ = \frac{5 π}{4}, θ = \frac{π}{4}, θ = \frac{7 π}{4}

Pasos de solución

sec^{2} (θ) tan (θ) = 2 tan (θ), 0^{\circ} \leq θ \leq 36 0^{\circ}

Restar

2 tan (θ)

de ambos lados

sec^{2} (θ) tan (θ) - 2 tan (θ) = 0

Factorizar

sec^{2} (θ) tan (θ) - 2 tan (θ) : tan (θ) (sec (θ) + 2) (sec (θ) - 2)

sec^{2} (θ) tan (θ) - 2 tan (θ)

Factorizar el termino común

tan (θ)

= tan (θ) (sec^{2} (θ) - 2)

Factorizar

sec^{2} (θ) - 2 : (sec (θ) + 2) (sec (θ) - 2)

sec^{2} (θ) - 2

Aplicar las leyes de los exponentes:

a = (a)^{2}

2 = (2)^{2}

= sec^{2} (θ) - (2)^{2}

Aplicar la siguiente regla para binomios al cuadrado:

x^{2} - y^{2} = (x + y) (x - y)

sec^{2} (θ) - (2)^{2} = (sec (θ) + 2) (sec (θ) - 2)

= (sec (θ) + 2) (sec (θ) - 2)

= tan (θ) (sec (θ) + 2) (sec (θ) - 2)

tan (θ) (sec (θ) + 2) (sec (θ) - 2) = 0

Resolver cada parte por separado

tan (θ) = 0 or sec (θ) + 2 = 0 or sec (θ) - 2 = 0

tan (θ) = 0, 0 \leq θ \leq 36 0^{\circ} : θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}

tan (θ) = 0, 0 \leq θ \leq 36 0^{\circ}

Soluciones generales para

tan (θ) = 0

tan (x)

tabla de valores periódicos con

18 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = 0 + 18 0^{\circ} n

θ = 0 + 18 0^{\circ} n

Resolver

θ = 0 + 18 0^{\circ} n : θ = 18 0^{\circ} n

θ = 0 + 18 0^{\circ} n

0 + 18 0^{\circ} n = 18 0^{\circ} n

θ = 18 0^{\circ} n

θ = 18 0^{\circ} n

Soluciones para el rango

0 \leq θ \leq 36 0^{\circ}

θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}

sec (θ) + 2 = 0, 0 \leq θ \leq 36 0^{\circ} : θ = 13 5^{\circ}, θ = 22 5^{\circ}

sec (θ) + 2 = 0, 0 \leq θ \leq 36 0^{\circ}

Mover

2

al lado derecho

sec (θ) + 2 = 0

Restar

2

de ambos lados

sec (θ) + 2 - 2 = 0 - 2

Simplificar

sec (θ) = - 2

sec (θ) = - 2

Soluciones generales para

sec (θ) = - 2

sec (x)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = 13 5^{\circ} + 36 0^{\circ} n, θ = 22 5^{\circ} + 36 0^{\circ} n

θ = 13 5^{\circ} + 36 0^{\circ} n, θ = 22 5^{\circ} + 36 0^{\circ} n

Soluciones para el rango

0 \leq θ \leq 36 0^{\circ}

θ = 13 5^{\circ}, θ = 22 5^{\circ}

sec (θ) - 2 = 0, 0 \leq θ \leq 36 0^{\circ} : θ = 4 5^{\circ}, θ = 31 5^{\circ}

sec (θ) - 2 = 0, 0 \leq θ \leq 36 0^{\circ}

Mover

2

al lado derecho

sec (θ) - 2 = 0

Sumar

2

a ambos lados

sec (θ) - 2 + 2 = 0 + 2

Simplificar

sec (θ) = 2

sec (θ) = 2

Soluciones generales para

sec (θ) = 2

sec (x)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 31 5^{\circ} + 36 0^{\circ} n

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 31 5^{\circ} + 36 0^{\circ} n

Soluciones para el rango

0 \leq θ \leq 36 0^{\circ}

θ = 4 5^{\circ}, θ = 31 5^{\circ}

Combinar toda las soluciones

θ = 0, θ = 18 0^{\circ}, θ = 36 0^{\circ}, θ = 13 5^{\circ}, θ = 22 5^{\circ}, θ = 4 5^{\circ}, θ = 31 5^{\circ}

Ejemplos populares

arccos(x)=180

arccos (x) = 18 0^{\circ}

sin(a)=(29.7)/(54.5)

sin (a) = \frac{29.7}{54.5}

1.0003sin(30)=1.46sin(x)

1.0003 sin (3 0^{\circ}) = 1.46 sin (x)

3tan(x)+2cos(x)=0

3 tan (x) + 2 cos (x) = 0

(cos(x))(bsin(x)-a)=0,0<= x<2pi

(cos (x)) (b sin (x) - a) = 0, 0 \leq x < 2 π