English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor c,2=4sin(0.5(0-c))+2

Solución

resolver para

c, 2 = 4 sin (0.5 (0 - c)) + 2

Solución

c = - 4 πn, c = - 2 π - 4 πn

Grados

c = 0^{\circ} - 72 0^{\circ} n, c = - 36 0^{\circ} - 72 0^{\circ} n

Pasos de solución

2 = 4 sin (0.5 (0 - c)) + 2

Intercambiar lados

4 sin (0.5 (0 - c)) + 2 = 2

Restar

2

de ambos lados

4 sin (0.5 (0 - c)) + 2 - 2 = 2 - 2

Simplificar

4 sin (0.5 (0 - c)) = 0

Dividir ambos lados entre

4

4 sin (0.5 (0 - c)) = 0

Dividir ambos lados entre

4

\frac{4 sin ( 0.5 ( 0 - c ) )}{4} = \frac{0}{4}

Simplificar

sin (0.5 (0 - c)) = 0

sin (0.5 (0 - c)) = 0

Soluciones generales para

sin (0.5 (0 - c)) = 0

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

0.5 (0 - c) = 0 + 2 πn, 0.5 (0 - c) = π + 2 πn

0.5 (0 - c) = 0 + 2 πn, 0.5 (0 - c) = π + 2 πn

Resolver

0.5 (0 - c) = 0 + 2 πn : c = - 4 πn

0.5 (0 - c) = 0 + 2 πn

0 + 2 πn = 2 πn

0.5 (0 - c) = 2 πn

Multiplicar ambos lados por

10

0.5 (0 - c) = 2 πn

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere is one digit to the right of the decimal point, therefore multiply by

10

0.5 (0 - c) \cdot 10 = 2 πn \cdot 10

Simplificar

- 5 c = 20 πn

- 5 c = 20 πn

Dividir ambos lados entre

- 5

- 5 c = 20 πn

Dividir ambos lados entre

- 5

\frac{- 5 c}{- 5} = \frac{20 πn}{- 5}

Simplificar

\frac{- 5 c}{- 5} = \frac{20 πn}{- 5}

Simplificar

\frac{- 5 c}{- 5} : c

\frac{- 5 c}{- 5}

Aplicar las propiedades de las fracciones:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5 c}{5}

Dividir:

\frac{5}{5} = 1

= c

Simplificar

\frac{20 πn}{- 5} : - 4 πn

\frac{20 πn}{- 5}

Aplicar las propiedades de las fracciones:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{20 πn}{5}

Dividir:

\frac{20}{5} = 4

= - 4 πn

c = - 4 πn

c = - 4 πn

c = - 4 πn

Resolver

0.5 (0 - c) = π + 2 πn : c = - 2 π - 4 πn

0.5 (0 - c) = π + 2 πn

Multiplicar ambos lados por

10

0.5 (0 - c) = π + 2 πn

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere is one digit to the right of the decimal point, therefore multiply by

10

0.5 (0 - c) \cdot 10 = π 10 + 2 πn \cdot 10

Simplificar

- 5 c = 10 π + 20 πn

- 5 c = 10 π + 20 πn

Dividir ambos lados entre

- 5

- 5 c = 10 π + 20 πn

Dividir ambos lados entre

- 5

\frac{- 5 c}{- 5} = \frac{10 π}{- 5} + \frac{20 πn}{- 5}

Simplificar

\frac{- 5 c}{- 5} = \frac{10 π}{- 5} + \frac{20 πn}{- 5}

Simplificar

\frac{- 5 c}{- 5} : c

\frac{- 5 c}{- 5}

Aplicar las propiedades de las fracciones:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5 c}{5}

Dividir:

\frac{5}{5} = 1

= c

Simplificar

\frac{10 π}{- 5} + \frac{20 πn}{- 5} : - 2 π - 4 πn

\frac{10 π}{- 5} + \frac{20 πn}{- 5}

\frac{10 π}{- 5} = - 2 π

\frac{10 π}{- 5}

Aplicar las propiedades de las fracciones:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{10 π}{5}

Dividir:

\frac{10}{5} = 2

= - 2 π

= - 2 π + \frac{20 πn}{- 5}

\frac{20 πn}{- 5} = - 4 πn

\frac{20 πn}{- 5}

Aplicar las propiedades de las fracciones:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{20 πn}{5}

Dividir:

\frac{20}{5} = 4

= - 4 πn

= - 2 π - 4 πn

c = - 2 π - 4 πn

c = - 2 π - 4 πn

c = - 2 π - 4 πn

c = - 4 πn, c = - 2 π - 4 πn

Ejemplos populares

3cos^2(x)-2sqrt(3)cos(x)=cos(x)

3 cos^{2} (x) - 23 cos (x) = cos (x)

196sin(θ)-49cos(θ)=160

196 sin (θ) - 49 cos (θ) = 160

4tan(x)+3=-7

4 tan (x) + 3 = - 7

8tan(θ)+15=0

8 tan (θ) + 15 = 0

cos(x)=(48.4)/(54.5)

cos (x) = \frac{48.4}{54.5}