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sqrt(2)sin(x)=1,x>= 2pi,0

Solución

2 sin (x) = 1, x \geq 2 π, 0

x = \frac{9 π}{4}, x = \frac{11 π}{4}, x = \frac{17 π}{4}, x = \frac{19 π}{4}, x = \frac{25 π}{4}, x = \frac{27 π}{4}, x = \frac{33 π}{4}, x = \frac{35 π}{4}

Grados

x = 40 5^{\circ}, x = 49 5^{\circ}, x = 76 5^{\circ}, x = 85 5^{\circ}, x = 112 5^{\circ}, x = 121 5^{\circ}, x = 148 5^{\circ}, x = 157 5^{\circ}

Pasos de solución

2 sin (x) = 1, x \geq 2 π, 0

Dividir ambos lados entre

2

2 sin (x) = 1

Dividir ambos lados entre

2

\frac{2 sin ( x )}{2} = \frac{1}{2}

Simplificar

\frac{2 sin ( x )}{2} = \frac{1}{2}

Simplificar

\frac{2 sin ( x )}{2} : sin (x)

\frac{2 sin ( x )}{2}

Eliminar los terminos comunes:

2

= sin (x)

Simplificar

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

Multiplicar por el conjugado

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Aplicar las leyes de los exponentes:

a a = a

22 = 2

= 2

= \frac{2}{2}

sin (x) = \frac{2}{2}

sin (x) = \frac{2}{2}

sin (x) = \frac{2}{2}

Soluciones generales para

sin (x) = \frac{2}{2}

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Soluciones para el rango

x \geq 2 π

x = \frac{9 π}{4}, x = \frac{11 π}{4}, x = \frac{17 π}{4}, x = \frac{19 π}{4}, x = \frac{25 π}{4}, x = \frac{27 π}{4}, x = \frac{33 π}{4}, x = \frac{35 π}{4}

2^{a r c c o s (x)} + 4^{a r c c o s (x) + 1} - 2 = 3

csc (θ) cos (θ) sin (θ) = 1

3 cos (x) + sin (2 x) = 0

tan (α) = 0.875

sin (x) = \frac{18}{31}