sin(b)=((250km)/(590km))sin(23),82

Solución

sin (b) = (\frac{250 km}{590 km}) sin (2 3^{\circ}), 8 2^{\circ}

Sin soluci \overset{o}{ˊ} n para b \in R

Pasos de solución

sin (b) = (\frac{250 km}{590 km}) sin (2 3^{\circ}), 8 2^{\circ}

Simplificar

\frac{250 km}{590 km} sin (2 3^{\circ}) : \frac{25 sin ( 2 3 ^{\circ} )}{59}

\frac{250 km}{590 km} sin (2 3^{\circ})

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{250 km sin ( 2 3 ^{\circ} )}{590 km}

Eliminar los terminos comunes:

k

= \frac{250 m sin ( 2 3 ^{\circ} )}{590 m}

Eliminar los terminos comunes:

m

= \frac{250 sin ( 2 3 ^{\circ} )}{590}

Eliminar los terminos comunes:

10

= \frac{25 sin ( 2 3 ^{\circ} )}{59}

Aplicar propiedades trigonométricas inversas

sin (b) = \frac{25 sin ( 2 3 ^{\circ} )}{59}

Soluciones generales para

sin (b) = \frac{25 sin ( 2 3 ^{\circ} )}{59}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{25 sin ( 2 3 ^{\circ} )}{59}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{25 sin ( 2 3 ^{\circ} )}{59}) + 36 0^{\circ} n

b = arcsin (\frac{25 sin ( 2 3 ^{\circ} )}{59}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{25 sin ( 2 3 ^{\circ} )}{59}) + 36 0^{\circ} n

Soluciones para el rango

8 2^{\circ}

Sin soluci \overset{o}{ˊ} n para b \in R

sin (x) = \frac{30}{60}

4 cos (z) + 5 = 0

y, sin (x^{2} y^{2}) = x

5 + 4 cos (θ) = 0

- sec^{2} (x) + tan (x) + 1 = 0