English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(tan^2(b)+1)/(tan(b))=csc^2(b)

Solución

\frac{tan ^{2} ( b ) + 1}{tan ( b )} = csc^{2} (b)

Solución

b = \frac{π}{4} + πn

Grados

b = 4 5^{\circ} + 18 0^{\circ} n

Pasos de solución

\frac{tan ^{2} ( b ) + 1}{tan ( b )} = csc^{2} (b)

Restar

csc^{2} (b)

de ambos lados

\frac{tan ^{2} ( b ) + 1}{tan ( b )} - csc^{2} (b) = 0

Simplificar

\frac{tan ^{2} ( b ) + 1}{tan ( b )} - csc^{2} (b) : \frac{tan ^{2} ( b ) + 1 - csc ^{2} ( b ) tan ( b )}{tan ( b )}

\frac{tan ^{2} ( b ) + 1}{tan ( b )} - csc^{2} (b)

Convertir a fracción:

csc^{2} (b) = \frac{csc ^{2} ( b ) tan ( b )}{tan ( b )}

= \frac{tan ^{2} ( b ) + 1}{tan ( b )} - \frac{csc ^{2} ( b ) tan ( b )}{tan ( b )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{tan ^{2} ( b ) + 1 - csc ^{2} ( b ) tan ( b )}{tan ( b )}

\frac{tan ^{2} ( b ) + 1 - csc ^{2} ( b ) tan ( b )}{tan ( b )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

tan^{2} (b) + 1 - csc^{2} (b) tan (b) = 0

Re-escribir usando identidades trigonométricas

1 + tan^{2} (b) - csc^{2} (b) tan (b)

Utilizar la identidad pitagórica:

csc^{2} (x) = 1 + cot^{2} (x)

= 1 + tan^{2} (b) - (1 + cot^{2} (b)) tan (b)

Utilizar la identidad trigonométrica básica:

tan (x) = \frac{1}{cot ( x )}

= 1 + (\frac{1}{cot ( b )})^{2} - (1 + cot^{2} (b)) \frac{1}{cot ( b )}

Simplificar

1 + (\frac{1}{cot ( b )})^{2} - (1 + cot^{2} (b)) \frac{1}{cot ( b )} : 1 + \frac{1}{cot ^{2} ( b )} - \frac{1 + cot ^{2} ( b )}{cot ( b )}

1 + (\frac{1}{cot ( b )})^{2} - (1 + cot^{2} (b)) \frac{1}{cot ( b )}

(\frac{1}{cot ( b )})^{2} = \frac{1}{cot ^{2} ( b )}

(\frac{1}{cot ( b )})^{2}

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cot ^{2} ( b )}

Aplicar la regla

1^{a} = 1

1^{2} = 1

= \frac{1}{cot ^{2} ( b )}

(1 + cot^{2} (b)) \frac{1}{cot ( b )} = \frac{1 + cot ^{2} ( b )}{cot ( b )}

(1 + cot^{2} (b)) \frac{1}{cot ( b )}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 + cot ^{2} ( b ) )}{cot ( b )}

1 \cdot (1 + cot^{2} (b)) = 1 + cot^{2} (b)

1 \cdot (1 + cot^{2} (b))

Multiplicar:

1 \cdot (1 + cot^{2} (b)) = (1 + cot^{2} (b))

= (1 + cot^{2} (b))

Quitar los parentesis:

(a) = a

= 1 + cot^{2} (b)

= \frac{1 + cot ^{2} ( b )}{cot ( b )}

= 1 + \frac{1}{cot ^{2} ( b )} - \frac{cot ^{2} ( b ) + 1}{cot ( b )}

= 1 + \frac{1}{cot ^{2} ( b )} - \frac{1 + cot ^{2} ( b )}{cot ( b )}

1 - \frac{1 + cot ^{2} ( b )}{cot ( b )} + \frac{1}{cot ^{2} ( b )} = 0

Usando el método de sustitución

1 - \frac{1 + cot ^{2} ( b )}{cot ( b )} + \frac{1}{cot ^{2} ( b )} = 0

Sea:

cot (b) = u

1 - \frac{1 + u ^{2}}{u} + \frac{1}{u ^{2}} = 0

1 - \frac{1 + u ^{2}}{u} + \frac{1}{u ^{2}} = 0 : u = 1, u = i, u = - i

1 - \frac{1 + u ^{2}}{u} + \frac{1}{u ^{2}} = 0

Multiplicar por el mínimo común múltiplo

1 - \frac{1 + u ^{2}}{u} + \frac{1}{u ^{2}} = 0

Encontrar el mínimo común múltiplo de

u, u^{2} : u^{2}

u, u^{2}

Mínimo común múltiplo (MCM)

Calcular una expresión que este compuesta de factores que aparezcan tanto en

u

u^{2}

= u^{2}

Multiplicar por el mínimo común múltiplo=

u^{2}

1 \cdot u^{2} - \frac{1 + u ^{2}}{u} u^{2} + \frac{1}{u ^{2}} u^{2} = 0 \cdot u^{2}

Simplificar

1 \cdot u^{2} - \frac{1 + u ^{2}}{u} u^{2} + \frac{1}{u ^{2}} u^{2} = 0 \cdot u^{2}

Simplificar

1 \cdot u^{2} : u^{2}

1 \cdot u^{2}

Multiplicar:

1 \cdot u^{2} = u^{2}

= u^{2}

Simplificar

- \frac{1 + u ^{2}}{u} u^{2} : - u (u^{2} + 1)

- \frac{1 + u ^{2}}{u} u^{2}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{( 1 + u ^{2} ) u ^{2}}{u}

Eliminar los terminos comunes:

u

= - u (u^{2} + 1)

Simplificar

\frac{1}{u ^{2}} u^{2} : 1

\frac{1}{u ^{2}} u^{2}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ^{2}}{u ^{2}}

Eliminar los terminos comunes:

u^{2}

= 1

Simplificar

0 \cdot u^{2} : 0

0 \cdot u^{2}

Aplicar la regla

0 \cdot a = 0

= 0

u^{2} - u (u^{2} + 1) + 1 = 0

u^{2} - u (u^{2} + 1) + 1 = 0

u^{2} - u (u^{2} + 1) + 1 = 0

Resolver

u^{2} - u (u^{2} + 1) + 1 = 0 : u = 1, u = i, u = - i

u^{2} - u (u^{2} + 1) + 1 = 0

Desarrollar

u^{2} - u (u^{2} + 1) + 1 : u^{2} - u^{3} - u + 1

u^{2} - u (u^{2} + 1) + 1

Expandir

- u (u^{2} + 1) : - u^{3} - u

- u (u^{2} + 1)

Poner los parentesis utilizando:

a (b + c) = ab + a c

a = - u, b = u^{2}, c = 1

= - u u^{2} + (- u) \cdot 1

Aplicar las reglas de los signos

+ (- a) = - a

= - u^{2} u - 1 \cdot u

Simplificar

- u^{2} u - 1 \cdot u : - u^{3} - u

- u^{2} u - 1 \cdot u

u^{2} u = u^{3}

u^{2} u

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u = u^{2 + 1}

= u^{2 + 1}

Sumar:

2 + 1 = 3

= u^{3}

1 \cdot u = u

1 \cdot u

Multiplicar:

1 \cdot u = u

= u

= - u^{3} - u

= - u^{3} - u

= u^{2} - u^{3} - u + 1

u^{2} - u^{3} - u + 1 = 0

Escribir en la forma binómica

a_{n} x^{n} + \dots + a_{1} x + b = 0

- u^{3} + u^{2} - u + 1 = 0

Factorizar

- u^{3} + u^{2} - u + 1 : - (u - 1) (u^{2} + 1)

- u^{3} + u^{2} - u + 1

Factorizar el termino común

- 1

= - (u^{3} - u^{2} + u - 1)

Factorizar

u^{3} - u^{2} + u - 1 : (u - 1) (u^{2} + 1)

u^{3} - u^{2} + u - 1

= (u^{3} - u^{2}) + (u - 1)

Factorizar

u^{2}

u^{3} - u^{2}

u^{2} (u - 1)

u^{3} - u^{2}

Aplicar las leyes de los exponentes:

a^{b + c} = a^{b} a^{c}

u^{3} = u u^{2}

= u u^{2} - u^{2}

Factorizar el termino común

u^{2}

= u^{2} (u - 1)

= (u - 1) + u^{2} (u - 1)

Factorizar el termino común

u - 1

= (u - 1) (u^{2} + 1)

= - (u - 1) (u^{2} + 1)

- (u - 1) (u^{2} + 1) = 0

Utilizando el teorema de factor cero: si

ab = 0

entonces

a = 0

b = 0

u - 1 = 0 or u^{2} + 1 = 0

Resolver

u - 1 = 0 : u = 1

u - 1 = 0

Mover

1

al lado derecho

u - 1 = 0

Sumar

1

a ambos lados

u - 1 + 1 = 0 + 1

Simplificar

u = 1

u = 1

Resolver

u^{2} + 1 = 0 : u = i, u = - i

u^{2} + 1 = 0

Mover

1

al lado derecho

u^{2} + 1 = 0

Restar

1

de ambos lados

u^{2} + 1 - 1 = 0 - 1

Simplificar

u^{2} = - 1

u^{2} = - 1

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = - 1, u = - - 1

Simplificar

- 1 : i

- 1

Aplicar las propiedades de los numeros imaginarios:

- 1 = i

= i

Simplificar

- - 1 : - i

- - 1

Aplicar las propiedades de los numeros imaginarios:

- 1 = i

= - i

u = i, u = - i

Las soluciones son

u = 1, u = i, u = - i

u = 1, u = i, u = - i

Verificar las soluciones

Encontrar los puntos no definidos (singularidades):

u = 0

Tomar el(los) denominador(es) de

1 - \frac{1 + u ^{2}}{u} + \frac{1}{u ^{2}}

y comparar con cero

u = 0

Resolver

u^{2} = 0 : u = 0

u^{2} = 0

Aplicar la regla

x^{n} = 0 \Rightarrow x = 0

u = 0

Los siguientes puntos no están definidos

u = 0

Combinar los puntos no definidos con las soluciones:

u = 1, u = i, u = - i

Sustituir en la ecuación

u = cot (b)

cot (b) = 1, cot (b) = i, cot (b) = - i

cot (b) = 1, cot (b) = i, cot (b) = - i

cot (b) = 1 : b = \frac{π}{4} + πn

cot (b) = 1

Soluciones generales para

cot (b) = 1

cot (x)

tabla de valores periódicos con

πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

b = \frac{π}{4} + πn

b = \frac{π}{4} + πn

cot (b) = i :

Sin solución

cot (b) = i

Sin soluci \overset{o}{ˊ} n

cot (b) = - i :

Sin solución

cot (b) = - i

Sin soluci \overset{o}{ˊ} n

Combinar toda las soluciones

b = \frac{π}{4} + πn

Ejemplos populares

solvefor x,r+s+6t=cos(2x+y)resolver para

x, r + s + 6 t = cos (2 x + y)

(tan^2(b)+1)/((tan(x)))=csc^2(b)

\frac{tan ^{2} ( b ) + 1}{( tan ( x ) )} = csc^{2} (b)

sin(x)+sin^2(x/2)= 1/2

sin (x) + sin^{2} (\frac{x}{2}) = \frac{1}{2}

sin^5(x)+sin^3(x)=0

sin^{5} (x) + sin^{3} (x) = 0

5sin^2(x)cos(7x)-cos(7x)=0

5 sin^{2} (x) cos (7 x) - cos (7 x) = 0