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(cos^{2022}(x))/((sin^{2022)(x)+cos^{2022}(x))}=1

Solución

\frac{cos ^{2022} ( x )}{( sin ^{2022} ( x ) + cos ^{2022} ( x ) )} = 1

x = 2 πn, x = π + 2 πn

Grados

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Pasos de solución

\frac{cos ^{2022} ( x )}{( sin ^{2022} ( x ) + cos ^{2022} ( x ) )} = 1

Restar

1

de ambos lados

\frac{cos ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )} - 1 = 0

Simplificar

\frac{cos ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )} - 1 : - \frac{sin ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

\frac{cos ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )} - 1

Convertir a fracción:

1 = \frac{1 ( sin ^{2022} ( x ) + cos ^{2022} ( x ) )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

= \frac{cos ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )} - \frac{1 \cdot ( sin ^{2022} ( x ) + cos ^{2022} ( x ) )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ^{2022} ( x ) - 1 \cdot ( sin ^{2022} ( x ) + cos ^{2022} ( x ) )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

Multiplicar:

1 \cdot (sin^{2022} (x) + cos^{2022} (x)) = (sin^{2022} (x) + cos^{2022} (x))

= \frac{cos ^{2022} ( x ) - ( sin ^{2022} ( x ) + cos ^{2022} ( x ) )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

Expandir

cos^{2022} (x) - (sin^{2022} (x) + cos^{2022} (x)) : - sin^{2022} (x)

cos^{2022} (x) - (sin^{2022} (x) + cos^{2022} (x))

- (sin^{2022} (x) + cos^{2022} (x)) : - sin^{2022} (x) - cos^{2022} (x)

- (sin^{2022} (x) + cos^{2022} (x))

Poner los parentesis

= - (sin^{2022} (x)) - (cos^{2022} (x))

Aplicar las reglas de los signos

+ (- a) = - a

= - sin^{2022} (x) - cos^{2022} (x)

= cos^{2022} (x) - sin^{2022} (x) - cos^{2022} (x)

Sumar elementos similares:

cos^{2022} (x) - cos^{2022} (x) = 0

= - sin^{2022} (x)

= \frac{- sin ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

Aplicar las propiedades de las fracciones:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{sin ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )}

- \frac{sin ^{2022} ( x )}{sin ^{2022} ( x ) + cos ^{2022} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- (sin^{2022} (x)) = 0

Dividir ambos lados entre

- 1

- (sin^{2022} (x)) = 0

Dividir ambos lados entre

- 1

\frac{- sin ^{2022} ( x )}{- 1} = \frac{0}{- 1}

Simplificar

sin^{2022} (x) = 0

sin^{2022} (x) = 0

Utilizando el teorema de factor cero: si

ab = 0

entonces

a = 0

b = 0

sin (x) = 0

La solución es

sin (x) = 0

Soluciones generales para

sin (x) = 0

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Resolver

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

5 sec (x) - 4 cos (x) = 8

sin^{3} (x) = - 1

x, sin^{2} (x) = \frac{( 1 - cos ( y ) )}{2}

sin (x) + sin^{2} (x) + cos (x) + cos^{2} (x) = 0

4 cos^{2} (x) - 4 sin (x) - 1 = 0