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4(sin(150))(cos(210))+3(tan(240))

Solución

4 (sin (15 0^{\circ})) (cos (21 0^{\circ})) + 3 (tan (24 0^{\circ}))

23

Notación decimal

3.46410 \dots

Pasos de solución

4 (sin (15 0^{\circ})) (cos (21 0^{\circ})) + 3 (tan (24 0^{\circ}))

= 4 sin (15 0^{\circ}) cos (21 0^{\circ}) + 3 tan (24 0^{\circ})

Re-escribir usando identidades trigonométricas:

4 sin (15 0^{\circ}) cos (21 0^{\circ}) = 2 (sin (0) - sin (6 0^{\circ}))

4 sin (15 0^{\circ}) cos (21 0^{\circ})

Utilizar la identidad producto-suma:

sin (s) cos (t) = \frac{1}{2} (sin (s + t) + sin (s - t))

= 4 \cdot \frac{1}{2} (sin (15 0^{\circ} + 21 0^{\circ}) + sin (15 0^{\circ} - 21 0^{\circ}))

Simplificar

= 2 (sin (36 0^{\circ}) + sin (- 6 0^{\circ}))

Utilizar la siguiente propiedad:

sin (- x) = - sin (x)

sin (- 6 0^{\circ}) = - sin (6 0^{\circ})

= 2 (sin (36 0^{\circ}) - sin (6 0^{\circ}))

sin (36 0^{\circ}) = sin (0)

sin (36 0^{\circ})

Reescribir

36 0^{\circ}

como

36 0^{\circ} + 0

= sin (36 0^{\circ} + 0)

Utilizar la periodicidad de

sin

sin (x + 36 0^{\circ}) = sin (x)

sin (36 0^{\circ} + 0) = sin (0)

= sin (0)

= 2 (sin (0) - sin (6 0^{\circ}))

= 2 (sin (0) - sin (6 0^{\circ})) + 3 tan (24 0^{\circ})

tan (24 0^{\circ}) = tan (6 0^{\circ})

tan (24 0^{\circ})

Reescribir

24 0^{\circ}

como

18 0^{\circ} + 6 0^{\circ}

= tan (18 0^{\circ} + 6 0^{\circ})

Utilizar la periodicidad de

tan

tan (x + 18 0^{\circ}) = tan (x)

tan (18 0^{\circ} + 6 0^{\circ}) = tan (6 0^{\circ})

= tan (6 0^{\circ})

= 2 (sin (0) - sin (6 0^{\circ})) + 3 tan (6 0^{\circ})

Utilizar la siguiente identidad trivial:

sin (0) = 0

sin (0)

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Utilizar la siguiente identidad trivial:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

tabla de valores periódicos con

36 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

Utilizar la siguiente identidad trivial:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

tabla de valores periódicos con

18 0^{\circ} n

intervalos:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= 2 (0 - \frac{3}{2}) + 33

Simplificar

2 (0 - \frac{3}{2}) + 33 : 23

2 (0 - \frac{3}{2}) + 33

2 (0 - \frac{3}{2}) = - 3

2 (0 - \frac{3}{2})

0 - \frac{3}{2} = - \frac{3}{2}

= 2 (- \frac{3}{2})

Quitar los parentesis:

(- a) = - a

= - 2 \cdot \frac{3}{2}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 \cdot 2}{2}

Eliminar los terminos comunes:

2

= - 3

= - 3 + 33

Sumar elementos similares:

- 3 + 33 = 23

= 23

= 23

30 sin (1 0^{\circ})

cos (3 (\frac{2 π}{3}))

cos (2 5^{\circ}) cos (2 0^{\circ}) - sin (2 5^{\circ}) sin (2 0^{\circ})

[2 (cos (\frac{π}{3}) + i sin (\frac{π}{3}))]^{4}

\frac{5}{sin ( 4 0 ^{\circ} )}