es

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Joshua is twice as old as his brother Carlo. In 10 years, the sum of their ages will be 45. How old are they now?

Solución

Joshua is twice as old as his brother Carlo. In 10 years, the sum of their ages will be 45. How old are they now?

Solución

Carlo^{'} s age is : 8 \frac{1}{3}

Joshua^{'} s age is : 16 \frac{2}{3}

Pasos de solución

Translate the problem into an equation:

2 x + 10 + x + 10 = 45

Resolver para

x, 2 x + 10 + x + 10 = 45 : x = \frac{25}{3}

Hallar age

Carlo^{'} s age is : 8 \frac{1}{3}

Joshua^{'} s age is : 16 \frac{2}{3}

Ejemplos populares

Jess is three years older than Mike. Twenty years from now, the sum of their ages would be 51. How old is Jess today?Maria is 37 years old. The sum of the ages of Maria and Paul is 91. How old is Paul?Bill is twice as old as Bob. Bob is 3 years old. How old is Bill?Jenny is twice as old as Nicole. In 5 years, the sum of their ages will be 43.Find their ages three years ago.Five years ago, Nina was twice as old as Sam. In five years, she will be 1.5 times as old as Sam. How old are Nina and Sam right now?