es

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

The sum of the ages of Jose and Mackenzie is 100 years. 10 years ago, Jose's age was 3 times Mackenzie's age. How old is Jose now?

Solución

The sum of the ages of Jose and Mackenzie is 100 years. 10 years ago, Jose's age was 3 times Mackenzie's age. How old is Jose now?

Solución

Jose^{'} s age is : 70

Pasos de solución

Translate the problem into an equation:

x - 10 = 3 (100 - x - 10)

Resolver para

x, x - 10 = 3 (100 - x - 10) : x = 70

Jose^{'} s age is : 70

Ejemplos populares

The sum of the ages of Juwan and Riley is 66 years. 6 years ago, Juwan's age was 2 times Riley's age. How old is Juwan now?kathy is 7 years younger than brian. the sum of their ages is 84 how old is brian allison is 3 years younger than her sister. the sum of their ages is 25 how old is allisons sister Gregory is 2 years older than Vivian. In 9 years the sum of their ages will be 84. How old is Gregory now?Cameron is 22 years younger than Caitlyn. 3 years ago, Caitlyn's age was 2 times Cameron's age. How old is Cameron now?