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פּוֹפּוּלָרִי >

Find three consecutive integers such that 16 more than half of the larger number is two thirds of the smallest number.

פתרון

Find three consecutive integers such that 16 more than half of the larger number is two thirds of the smallest number.

פתרון

The numbers : 102, 103, 104

צעדי פתרון

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x

פתור את:

x = 102

x + 1 = 102 + 1 = 103

x + 2 = 102 + 2 = 104

The numbers : 102, 103, 104

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