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Popular >

the sum of the squares of two consecutive integers is 580.

Solución

the sum of the squares of two consecutive integers is 580.

Solución

The numbers : \frac{- 1 + 1159}{2}, \frac{- 1 + 1159}{2} + 1 or - \frac{1 + 1159}{2}, - \frac{1 + 1159}{2} + 1

Pasos de solución

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 580

Resolver

x^{2} + (x + 1)^{2} = 580 : x = \frac{- 1 + 1159}{2}, x = - \frac{1 + 1159}{2}

Sustituir

x = \frac{- 1 + 1159}{2} : \frac{- 1 + 1159}{2} + 1

Sustituir

x = - \frac{1 + 1159}{2} : - \frac{1 + 1159}{2} + 1

The numbers : \frac{- 1 + 1159}{2}, \frac{- 1 + 1159}{2} + 1 or - \frac{1 + 1159}{2}, - \frac{1 + 1159}{2} + 1

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