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arccsc(2x)+arcsin(0)=arctan(1/(sqrt(3)))

Solución

arccsc (2 x) + arcsin (0) = arctan (\frac{1}{3})

x = 1

Pasos de solución

arccsc (2 x) + arcsin (0) = arctan (\frac{1}{3})

arcsin (0) = 0

arcsin (0)

Utilizar la siguiente identidad trivial:

arcsin (0) = 0

arcsin (0)

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= 0

= 0

arctan (\frac{1}{3}) = \frac{π}{6}

arctan (\frac{1}{3})

Utilizar la siguiente identidad trivial:

arctan (\frac{1}{3}) = \frac{π}{6}

arctan (\frac{1}{3})

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{6}

= \frac{π}{6}

arccsc (2 x) + 0 = \frac{π}{6}

arccsc (2 x) + 0 = arccsc (2 x)

arccsc (2 x) = \frac{π}{6}

Aplicar propiedades trigonométricas inversas

arccsc (2 x) = \frac{π}{6}

arccsc (x) = a \Rightarrow x = csc (a)

2 x = csc (\frac{π}{6})

csc (\frac{π}{6}) = 2

csc (\frac{π}{6})

Utilizar la siguiente identidad trivial:

csc (\frac{π}{6}) = 2

csc (\frac{π}{6})

csc (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

= 2

= 2

2 x = 2

2 x = 2

Resolver

2 x = 2 : x = 1

2 x = 2

Dividir ambos lados entre

2

2 x = 2

Dividir ambos lados entre

2

\frac{2 x}{2} = \frac{2}{2}

Simplificar

x = 1

x = 1

x = 1

sin (t) + cos (2 t) = 0.75

2 cos (x) = cot (x)

3 cos (x) + sin (x) = 2

cos (2 t) - cos (t) = - 0.5

sin^{2} (x) - cos (x) + 1 = 0