solvefor x,1sin(25)=1.51sin(x)

Solución

resolver para

x, 1 sin (2 5^{\circ}) = 1.51 sin (x)

x = 0.28366 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.28366 \dots + 36 0^{\circ} n

radianes

x = 0.28366 \dots + 2 πn, x = π - 0.28366 \dots + 2 πn

Pasos de solución

1 \cdot sin (2 5^{\circ}) = 1.51 sin (x)

Intercambiar lados

1.51 sin (x) = 1 \cdot sin (2 5^{\circ})

Multiplicar:

1 \cdot sin (2 5^{\circ}) = sin (2 5^{\circ})

1.51 sin (x) = sin (2 5^{\circ})

Dividir ambos lados entre

1.51

1.51 sin (x) = sin (2 5^{\circ})

Dividir ambos lados entre

1.51

\frac{1.51 sin ( x )}{1.51} = \frac{sin ( 2 5 ^{\circ} )}{1.51}

Simplificar

sin (x) = \frac{sin ( 2 5 ^{\circ} )}{1.51}

sin (x) = \frac{sin ( 2 5 ^{\circ} )}{1.51}

Aplicar propiedades trigonométricas inversas

sin (x) = \frac{sin ( 2 5 ^{\circ} )}{1.51}

Soluciones generales para

sin (x) = \frac{sin ( 2 5 ^{\circ} )}{1.51}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

x = arcsin (\frac{sin ( 2 5 ^{\circ} )}{1.51}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{sin ( 2 5 ^{\circ} )}{1.51}) + 36 0^{\circ} n

x = arcsin (\frac{sin ( 2 5 ^{\circ} )}{1.51}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{sin ( 2 5 ^{\circ} )}{1.51}) + 36 0^{\circ} n

Mostrar soluciones en forma decimal

x = 0.28366 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.28366 \dots + 36 0^{\circ} n

2 sin (θ) + cot (θ) = csc (θ)

cos (x) + 0.75 = 0

5 sin (c) + 21 = 0

0.47 \cdot 0.2 = 10 \cdot 9.8 sin (x)

5 sin (\frac{x}{2}) + 5 cos (x) = 0